(1/4)^2x+1=16

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Solution for (1/4)^2x+1=16 equation: 



(1/4)^2x+1=16

We move all terms to the left:

(1/4)^2x+1-(16)=0



Domain of the equation: 4)^2x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/4)^2x+1-16=0

We add all the numbers together, and all the variables

(+1/4)^2x-15=0

We multiply all the terms by the denominator


(+1-15*4)^2x=0

We add all the numbers together, and all the variables

(-59)^2x=0

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